Latihan tambahan

设定闹钟 = tetapkan jam loceng 闹钟只有 12 小时制，所以要把节目的 24 小时制时间改写。先看小时：比十二大，就减去十二，分钟照抄；再决定时段：Jam 1200 以后都是 p.m.。 例子：Jam 1905 → 19 − 12 = 7 → 7:05 p.m.。 注意：减完十二以后别忘了写 p.m.，写成 a.m. 闹钟就会在早上响。

setting an alarm = tetapkan jam loceng The alarm clock only uses the 12-hour system, so rewrite the programme's 24-hour time. If the hour is more than 12, subtract 12 and copy the minutes; then choose the part of the day: everything after Jam 1200 is p.m. Example: Jam 1905 → 19 − 12 = 7 → 7:05 p.m. Watch out: after subtracting 12, write p.m.; with a.m. the alarm would ring in the morning.

相加后比较 = tambah, kemudian banding 先把三段时间加起来：月和月加，年和年加。月数的和满十二就换成一年；月数里可能有两个十二，要全部换完。算出总时间以后，再和题目给的时间比较大小。 例子：1 年 8 个月 + 1 年 6 个月 + 9 个月 → 2 年 23 个月 → 3 年 11 个月，比 4 年少。 注意：没有进位的写法（月数十二以上）不是最后的答案。

add, then compare = tambah, kemudian banding First add the three periods: months with months and years with years. Every 12 months make a year, and the months may hold two 12s, so change them all. When you have the total, compare it with the time in the question. Example: 1 year 8 months + 1 year 6 months + 9 months → 2 years 23 months → 3 years 11 months, which is less than 4 years. Watch out: a total with 12 or more months has not been finished.

平均每艘 = purata sebuah 题目要平均每艘船用几个月，所以用除法。先把“几年几个月”全部换成月：年数乘十二，再加上月数；然后除以船的数目。最后用乘法检查：每艘的月数乘船数，应该等于总月数。 例子：1 年 10 个月造 2 条小船 → 22 个月 ÷ 2 = 每条 11 个月。 注意：换成月以后还要记得除，只换单位不除，得到的是全部的时间。

average for one = purata sebuah The question asks for the average months for one boat, so divide. First change the years and months into months (years × 12, plus the months), then divide by the number of boats. Check by multiplying back. Example: 2 small boats built in 1 year 10 months → 22 months ÷ 2 = 11 months each. Watch out: after changing to months you still have to divide; otherwise you have the whole time.

从毛虫到蝴蝶 = dari ulat hingga rama-rama 两段时间接在一起，求一共多少天，用加法，而且答案要用天。可以先把每段“几周几天”换成天（周数乘七再加天），再相加；也可以先加成几周几天，最后换成天。 例子：1 周 3 天 + 2 周 2 天 → 10 天 + 16 天 = 26 天。 注意：一周是七天，不是十天。

from caterpillar to butterfly = dari ulat hingga rama-rama The two periods follow each other, so add them, and give the answer in days. Change each weeks-and-days time into days (weeks × 7, plus the days) and add, or add first and change to days at the end. Example: 1 week 3 days + 2 weeks 2 days → 10 days + 16 days = 26 days. Watch out: a week is 7 days, not 10.

较晚开始 = bermula kemudian 电脑角是在图书馆开了一段时间以后才设立的，所以它存在的时间 = 图书馆的时间 − 晚开始的那段时间，用减法。先减月：月数不够减，就向年借一年换成十二个月；再减年，记得年已经少了一。 例子：11 年 1 个月 − 4 年 3 个月 → 10 年 13 个月 − 4 年 3 个月 → 6 年 10 个月。 注意：借位以后，年数要先减一再相减。

starting later = bermula kemudian The computer corner was added some time after the library opened, so its time = the library's time − the later start, which is a subtraction. Subtract the months first; if they are not enough, borrow 1 year as 12 months, then subtract the years, remembering they are 1 less. Example: 11 years 1 month − 4 years 3 months → 10 years 13 months − 4 years 3 months → 6 years 10 months. Watch out: after borrowing, take 1 from the years before subtracting.