Latihan
Latihan tambahan
5 soalan untuk mengukuhkan unit Selesaikan Masalah. Jika salah, baca petunjuk dan cuba lagi.
Harga sebuah traktor mini ialah RM7 385.40. Ladang Bukit Hijau membeli 3 buah dan Ladang Sri Tanjung membeli 5 buah. Berapakah jumlah yang dibayar oleh kedua-dua ladang?
合起来再乘 = gabung kemudian darab
两个农场买的是同一种拖拉机,价钱一样。可以先把两个农场买的台数加起来,再乘一台的价钱;也可以分别算两个农场,再相加。两种方法结果相同,第一种比较快。带仙的金额相乘,积要保留两位小数。
例子:一台 RM1 000.50,甲买 2 台、乙买 1 台 → 3 × RM1 000.50 = RM3 001.50。
注意:只算其中一个农场是不够的,题目问的是两个农场一共付多少。
combine, then multiply = gabung kemudian darab
Both farms buy the same tractor at the same price. Add the numbers of tractors first and multiply by the price of one, or work out each farm and add; both ways agree, and the first is quicker. When multiplying an amount with sen, keep two decimal places.
Example: one costs RM1 000.50; A buys 2 and B buys 1, so 3 × RM1 000.50 = RM3 001.50.
Watch out: working out only one farm is not enough; the question asks what both farms pay together.
Tahun lalu, Kelab Masakan mengutip RM1 860 daripada jualan kuih. Tahun ini kutipannya 4 kali kutipan tahun lalu. Berapakah jumlah kutipan bagi kedua-dua tahun?
倍数与总和 = kali ganda dan jumlah
这题有两步。第一步:今年是去年的四倍,“几倍”用乘法,求出今年的收入。第二步:题目问两年一共多少,所以要把今年和去年加起来。也可以想成一共是去年的五倍。
例子:去年 RM300,今年是去年的 3 倍 = RM900,两年共 RM1 200。
注意:只求出今年的收入还没有完成,要再加上去年的。
times as much, then the total = kali ganda dan jumlah
There are two steps. Step 1: this year is 4 times last year, and times means multiply, so find this year's amount. Step 2: the question asks for both years together, so add this year and last year. You can also think of it as 5 times last year.
Example: last year RM300, this year 3 times as much = RM900, both years RM1 200.
Watch out: finding this year's amount is not the end; add last year's too.
Harga 15 buah khemah yang sama ialah RM73 125. Kumpulan pengakap membeli 4 buah sahaja. Berapakah yang perlu dibayar?
先求一个 = cari harga seunit dahulu
知道很多个一共多少钱,要求其中几个的价钱,先用除法求一个的价钱,再乘要买的数目。除以十五时可以先列十五的乘法表。
例子:9 个水壶 RM270,一个 RM30,买 2 个付 RM60。
注意:求出一个的价钱以后不要停,还要乘上真正买的数目。
find one first = cari harga seunit dahulu
When you know the price of many and want the price of a few, first divide to find the price of one, then multiply by the number bought. For ÷ 15, list the 15 times table first.
Example: 9 water bottles cost RM270, so one is RM30, and 2 cost RM60.
Watch out: do not stop at the price of one; multiply by the number actually bought.
Sebuah bengkel mengenakan RM4 800 untuk membaiki 4 buah van yang sama rosaknya. Berapakah kos membaiki 5 buah van dengan kerosakan yang sama?
单位法 = kaedah seunit
修四辆车的费用已知,要求修五辆的费用。先除以四,求出修一辆车要多少钱;再乘五。这个“先求一个、再求几个”的方法叫单位法。
例子:修 3 台电脑 RM450,一台 RM150,修 2 台 RM300。
注意:不能直接用四辆的费用乘五,那样等于算了二十辆。
the unitary method = kaedah seunit
The cost for 4 vans is known and the cost for 5 is wanted. First divide by 4 to find the cost for one van, then multiply by 5. Finding one first and then several is called the unitary method.
Example: repairing 3 computers costs RM450, so one costs RM150 and 2 cost RM300.
Watch out: do not multiply the cost for 4 vans by 5; that would be 20 vans.
Tabung PIBG ada RM27 506.45. PIBG membayar RM9 800 untuk mengecat bangunan sekolah dan menerima sumbangan alumni RM6 215.70. Berapakah wang dalam tabung PIBG sekarang?
钱进钱出 = wang masuk, wang keluar
先把资料整理成表:原有的钱、钱出去(付油漆费)、钱进来(校友捐款)。钱出去要减,钱进来要加,从原有的钱开始一步一步算。整数金额要补点零零再和带仙的金额计算。
例子:原有 RM500,付出 RM200,收到 RM50 → RM500 − RM200 + RM50 = RM350。
注意:付出去的钱不能加,把所有金额都加起来是常见的错误。
money in, money out = wang masuk, wang keluar
First sort the facts into a table: the money at the start, money out (the painting) and money in (the alumni gift). Subtract money out and add money in, step by step from the starting amount. Write whole amounts with .00 before working with sen.
Example: start RM500, pay out RM200, receive RM50: RM500 − RM200 + RM50 = RM350.
Watch out: money paid out must not be added; adding every amount is a common mistake.
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