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Unit 15 · Selesaikan Masalah
Unit 15

Selesaikan Masalah

Masalah wang juga diselesaikan dengan empat langkah:
① Fahami soalan ② Fikir cara ③ Selesaikan ④ Semak
Cari kata kunci: jumlah, baki, setiap, sama banyak.

Selesaikan Masalah
解决金钱问题 = selesaikan masalah wang 金钱应用题也用四个步骤:理解题目、想方法、计算、检查。关键词可以帮助我们选运算:总数用加法;余额、剩下用减法;每一个一样多、几个一样的用乘法;平均分用除法。答案要写 RM 和答句。 例子:“每个 RM20,买 5 个,一共多少?”→ 乘法 → RM100。 注意:有两个问题的题目,要分两步做。
solving money problems = selesaikan masalah wang Money word problems use the same four steps: understand, plan, solve and check. Key words help choose the operation: total means add; balance or left means subtract; each or several of the same means multiply; shared equally means divide. Write RM and an answer sentence. Example: RM20 each, buy 5, how much altogether? Multiply: RM100. Watch out: a problem with two questions needs two steps.
Jumlah

Kos hari keluarga sekolah

Sekolah Seri Mutiara mengadakan hari keluarga. Kos makanan RM12 648.50, sewa khemah RM8 975 serta pentas dan sistem bunyi RM23 460. Berapakah kos keseluruhan hari keluarga itu?
Fahami soalan
• 3 jenis kos
• cari kos keseluruhan
Fikir cara
“keseluruhan” → tambah
Selesaikan
RM12 648.50 + RM8 975 + RM23 460
= RM45 083.50
Semak
RM45 083.50 − RM23 460 − RM8 975 = RM12 648.50 ✔
求总数 = cari jumlah 题目问家庭日的全部费用,关键词“全部、一共”表示用加法。把两个整数金额补点零零,小数点对齐,三个金额相加,得四万五千零八十三令吉五十仙。检查:用总数依次减去后两项,剩下的刚好是食物的费用。 例子:RM1 000 + RM2 500 + RM3 000.50 = RM6 500.50。 注意:补零以后仙的位置要对齐。
find the total = cari jumlah The question asks for the whole cost of the family day; words like whole and altogether mean add. Write the whole amounts with .00, line up the points and add: RM45 083.50. Check: take away the last two costs from the total and the food cost is left. Example: RM1 000 + RM2 500 + RM3 000.50 = RM6 500.50. Watch out: line up the sen after writing the zeros.
Wang masuk dan keluar

Tabung Kelab Robotik

Tabung Kelab Robotik ada RM18 240.75. Kelab itu membayar yuran pertandingan kebangsaan RM6 580. Selepas menang, kelab menerima hadiah RM12 500. Berapakah wang kelab sekarang?
Fahami soalan
PerkaraMasukKeluar
Yuran—6 580
Hadiah12 500—
ada 18 240.75
Fikir cara
keluar → tolak
masuk → tambah
Selesaikan
RM18 240.75 − RM6 580 = RM11 660.75
+ RM12 500 = RM24 160.75
Semak
RM24 160.75 − RM12 500 + RM6 580 = RM18 240.75 ✔
整理成表格 = susun dalam jadual 先把资料整理成“钱进、钱出、余额”的表:比赛报名费是钱出去,奖金是钱进来。然后从左到右算:一万八千二百四十令吉七十五仙减六千五百八十,得一万一千六百六十令吉七十五仙;再加一万二千五百,得两万四千一百六十令吉七十五仙。检查时倒过来:减去进来的,再加回出去的。 例子:RM1 000 − RM300 + RM200 = RM900。 注意:先分清楚每一笔是进还是出,才不会弄错加减。
organise in a table = susun dalam jadual First sort the facts into money in, money out and balance: the entry fee is money out and the prize is money in. Then work left to right: RM18 240.75 − RM6 580 = RM11 660.75, then + RM12 500 = RM24 160.75. To check, work backwards: take off the money in and add back the money out. Example: RM1 000 − RM300 + RM200 = RM900. Watch out: decide first whether each amount is in or out, so you add and subtract correctly.
Darab

Kerusi roda dalam seminggu

Sebuah kilang menghasilkan kerusi roda bernilai RM3 480 setiap hari. Kilang itu beroperasi 7 hari seminggu. Berapakah nilai kerusi roda yang dihasilkan dalam seminggu?
?
3 480
3 480
3 480
3 480
3 480
3 480
3 480
Fahami soalan
• 7 hari
• RM3 480 sehari
Fikir cara
7 bahagian sama → darab
Selesaikan
7 × RM3 480
= RM24 360
Semak
RM24 360 ÷ 7 = RM3 480 ✔
乘法应用 = masalah darab 条形图有七段一样长的格子,每段是一天生产的价值三千四百八十令吉,求一个星期的全部,所以用乘法:七乘三千四百八十,得两万四千三百六十令吉。检查:两万四千三百六十除以七,刚好回到三千四百八十。 例子:每天卖 RM1 200,5 天 → RM6 000。 注意:用除法检查乘法的答案。
a multiplication problem = masalah darab The bar model has 7 equal parts, one for each day's RM3 480; to find the whole week, multiply: 7 × RM3 480 = RM24 360. Check: RM24 360 ÷ 7 = RM3 480. Example: RM1 200 of sales a day for 5 days is RM6 000. Watch out: check a multiplication answer by dividing.
Darab dan bahagi

Hasil tiket bas dikongsi pemandu

Sebuah bas persiaran membuat 12 perjalanan pada musim cuti. Setiap perjalanan memperoleh hasil tiket RM4 250. Semua hasil itu dikongsi sama banyak oleh 6 orang pemandu. Berapakah yang diterima oleh seorang pemandu?
Fahami soalan
• 12 perjalanan × RM4 250
• dikongsi 6 pemandu
Fikir cara
darab, kemudian bahagi
Selesaikan
12 × RM4 250 = RM51 000
RM51 000 ÷ 6 = RM8 500
Semak
Cara lain: 12 ÷ 6 = 2
2 × RM4 250 = RM8 500 ✔
先乘后除 = darab kemudian bahagi 先求十二趟一共收了多少:十二乘四千二百五十,得五万一千令吉。再平均分给六位司机:五万一千除以六,每人得八千五百令吉。另一个方法:十二趟分给六人,每人等于分到两趟,二乘四千二百五十也是八千五百。 例子:4 趟各 RM300,分给 2 人 → 每人 RM600。 注意:先求总数再分,或者先约简,两种方法结果一样。
multiply then divide = darab kemudian bahagi First find the total for 12 trips: 12 × RM4 250 = RM51 000. Then share it among 6 drivers: RM51 000 ÷ 6 = RM8 500 each. Another way: 12 trips for 6 drivers is 2 trips each, and 2 × RM4 250 = RM8 500. Example: 4 trips of RM300 shared by 2 people is RM600 each. Watch out: finding the total first or simplifying first gives the same result.
Bahagi, darab, tolak

Set peralatan muzik

Harga 6 set peralatan muzik yang sama ialah RM57 600. Sekolah sudah menjelaskan bayaran untuk 4 set. Berapakah lagi yang perlu dibayar untuk set yang lain?
RM57 600
dibayar
dibayar
dibayar
dibayar
?
?
Fahami soalan
• 6 set sama harga
• 4 set sudah dibayar
Fikir cara
÷ 6 → harga 1 set
× 4, kemudian tolak
Selesaikan
RM57 600 ÷ 6 = RM9 600
4 × RM9 600 = RM38 400
RM57 600 − RM38 400 = RM19 200
Semak
Cara lain: 6 − 4 = 2 set
2 × RM9 600 = RM19 200 ✔
先除再乘再减 = bahagi, darab, tolak 先求一套的价钱:五万七千六百除以六,得九千六百令吉。已付四套:四乘九千六百,得三万八千四百令吉。还要付的就是总数减去已付的:五万七千六百减三万八千四百,得一万九千二百令吉。也可以直接想:还剩两套没付,二乘九千六百,一样是一万九千二百。 例子:3 本书 RM90,付了 1 本 → 还要付 RM60。 注意:条形图帮我们看清楚哪几段已付、哪几段还没付。
divide, multiply, subtract = bahagi, darab, tolak First find one set: RM57 600 ÷ 6 = RM9 600. Four sets are paid: 4 × RM9 600 = RM38 400. Still to pay: RM57 600 − RM38 400 = RM19 200. Or think directly: 2 sets are unpaid, and 2 × RM9 600 = RM19 200. Example: 3 books cost RM90 and 1 is paid, so RM60 is still to pay. Watch out: the bar model shows clearly which parts are paid and which are not.
Cuba

Belanjawan membina taman permainan ialah RM56 380.60. Kos buaian RM18 450 dan kos gelongsor RM21 095.35. Semua wang yang tinggal digunakan untuk membeli bangku. Berapakah wang untuk bangku?

求剩下的部分 = cari bahagian yang tinggal 预算是全部,秋千和滑梯是已经用掉的两部分,剩下的钱买长椅。所以用预算减去两项费用:可以一项一项减,也可以先把两项加起来再一次减。整数金额要补点零零,从仙开始借位。 例子:预算 RM1 000,用掉 RM300 和 RM450,剩 RM250。 注意:两项费用加起来只是用掉的钱,还要用预算去减。
find the part left = cari bahagian yang tinggal The budget is the whole; the swing and the slide are two parts already used, and what is left buys benches. So subtract both costs from the budget, one at a time or by adding them first and subtracting once. Write whole amounts with .00 and borrow from the sen. Example: budget RM1 000, costs RM300 and RM450, RM250 left. Watch out: the two costs added together are only the money used; you still subtract from the budget.
Cuba

Hasil jualan 12 buah basikal lipat yang sama ialah RM16 470. Berapakah harga sebuah basikal lipat?

求一个的价钱 = cari harga seunit 十二辆一样的折叠脚车一共卖得多少钱,一辆的价钱就是总数除以十二。先列十二的乘法表,再长除。除到个位还有余数时,补点零零继续除,商会有仙。最后用乘法检查。 例子:12 个书包卖 RM321,一个 RM321 ÷ 12 = RM26.75。 注意:商的小数点要和被除数的小数点对齐,仙一定写两位。
find the price of one = cari harga seunit Twelve identical folding bicycles earned the total, so one costs the total ÷ 12. List the 12 times table, then long-divide. If there is a remainder after the ones, write .00 and keep going; the answer will have sen. Check by multiplying. Example: 12 school bags sold for RM321, so one is RM321 ÷ 12 = RM26.75. Watch out: keep the answer's point in line with the amount's point and always write two sen digits.
Ringkasan

Syabas!

4 langkah

Cari kata kunci, pilih operasi, selesaikan dan semak. Tulis RM dalam jawapan.

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