Akal Pintar

余数决定最后两位 = baki menentukan dua digit terakhir 除以 100 时，最后两位数字就是余数。要余 42，所以十位放 4、个位放 2。这两张卡用掉以后，剩下 8、1、5。 例子：要余 07，最后两位就要是 0 和 7。 注意：顺序不能反，放成 24 余数就变 24 了。

the remainder fixes the last two digits = baki menentukan dua digit terakhir When dividing by 100, the last two digits are the remainder. For a remainder of 42, put 4 in the tens and 2 in the ones. That uses two cards and leaves 8, 1 and 5. Example: for a remainder of 07, the last two digits must be 0 and 7. Watch out: keep the order; 24 would give a remainder of 24.

商最大 = hasil bahagi paling besar 商就是前三位数字。要让商最大，就把剩下的 8、5、1 从大到小排：851。所以被除数是 85 142，85 142 ÷ 100 = 851 余 42。 例子：剩下 3、9、6，最大的排法是 963。 注意：如果题目要“商最小”，就要从小到大排。

the biggest quotient = hasil bahagi paling besar The quotient is the first three digits. To make it as big as possible, arrange the remaining 8, 5 and 1 from largest to smallest: 851. So the number is 85 142, and 85 142 ÷ 100 = 851 remainder 42. Example: with 3, 9 and 6 left, the largest arrangement is 963. Watch out: if the puzzle asked for the smallest quotient, arrange them from smallest to largest.

同样的方法 = cara yang sama 第一步看余数：除以 100 时，余数就是最后两位，所以余数决定了十位和个位要放哪两张卡。第二步，剩下的三张卡组成商；题目要商最大，就把它们从大到小排。最后把整个五位数除以 100 检查。 例子：卡片 3、7、1、6、5，余 16、商最大 → 最后两位是 1、6，剩下 3、7、5 排成 753，得 75 316。 注意：每张卡只能用一次；0 不能放在五位数的最前面。

the same method = cara yang sama Step 1 looks at the remainder: when dividing by 100 the remainder is the last two digits, so it decides which two cards go in the tens and ones. Step 2: the other three cards make the quotient; for the biggest quotient, arrange them from largest to smallest. Finally divide the five-digit number by 100 to check. Example: cards 3, 7, 1, 6, 5 with remainder 16 and the biggest quotient: the last two digits are 1 and 6, the rest make 753, giving 75 316. Watch out: each card is used only once, and 0 cannot be the first digit of the five-digit number.