Anu dalam Tolak

未知数是减数 = anu ialah nombor yang ditolak 用小数字想：9 − 3 = 6，而 3 = 9 − 6。所以当未知数是减去的数时，未知数 = 原来的数 − 剩下的数。84 − p = 29 → p = 84 − 29 = 55。 例子：70 − y = 42 → y = 70 − 42 = 28。 注意：这里还是用减法，但是换成“原来的数减剩下的数”。

the unknown is the number taken away = anu ialah nombor yang ditolak Think small: 9 − 3 = 6 and 3 = 9 − 6. So when the unknown is the number taken away, unknown = starting number − what is left. 84 − p = 29, so p = 84 − 29 = 55. Example: 70 − y = 42, so y = 70 − 42 = 28. Watch out: we still subtract, but it is the starting number minus the number left.

未知数是被减数 = anu ialah nombor asal 用小数字想：9 − 3 = 6，而 9 = 6 + 3。所以当未知数是原来的数时，要把剩下的数和减去的数加回来：q = 45 + 37 = 82。 例子：m − 150 = 300 → m = 300 + 150 = 450。 注意：这种情况要用加法，不是减法。

the unknown is the starting number = anu ialah nombor asal Think small: 9 − 3 = 6 and 9 = 6 + 3. So when the unknown is the starting number, add back the number that was taken away: q = 45 + 37 = 82. Example: m − 150 = 300, so m = 300 + 150 = 450. Watch out: this case uses addition, not subtraction.

求减数 = cari nombor yang ditolak 未知数 z 在减号后面，是“减去的数”。用小数字想：9 − 3 = 6，要找回 3，就用 9 − 6。所以减去的数 = 原来的数 − 剩下的数。从整千减时要连续借位，算完放回原式检查。 例子：900 − z = 350 → z = 900 − 350 = 550；检查 900 − 550 = 350。 注意：未知数在减号后面时要用减法求；如果用了加法，得数会比原来的数还大，一定不对。

find the number taken away = cari nombor yang ditolak The unknown z comes after the minus sign, so it is the number taken away. Think small: 9 − 3 = 6, and to get back the 3 we do 9 − 6. So the number taken away = starting number − what is left. Regroup across the zeros, then check in the sentence. Example: 900 − z = 350, so z = 900 − 350 = 550; check 900 − 550 = 350. Watch out: an unknown after the minus sign is found by subtracting; adding gives a number bigger than the starting number.

求被减数 = cari nombor asal 未知数 t 在减号前面，是“原来的数”。用小数字想：9 − 3 = 6，要找回 9，就用 6 + 3。所以原来的数 = 剩下的数 + 减去的数。算完放回原式，减一减看是不是等于剩下的数。 例子：t − 600 = 1 700 → t = 1 700 + 600 = 2 300；检查 2 300 − 600 = 1 700。 注意：未知数在减号前面时要用加法；用减法得到的数会比剩下的数还小，不可能是原来的数。

find the starting number = cari nombor asal The unknown t comes before the minus sign, so it is the starting number. Think small: 9 − 3 = 6, and to get back the 9 we do 6 + 3. So the starting number = what is left + the number taken away. Put it back and subtract to check. Example: t − 600 = 1 700, so t = 1 700 + 600 = 2 300; check 2 300 − 600 = 1 700. Watch out: an unknown before the minus sign is found by adding; subtracting gives a number smaller than what is left, which cannot be the start.