Latihan
Latihan tambahan
6 soalan untuk mengukuhkan unit Teroka Nombor. Jika salah, baca petunjuk dan cuba lagi.
Apakah nilai tempat bagi digit bergaris dalam 37 915?
数位 = nilai tempat
题目问有下划线的数字在哪个数位,要用位置的名称回答。五位数从左到右的数位是万位、千位、百位、十位、个位;也可以从右边的个位往左数。找到那个数字的位置,说出名称就行。
例子:在 64 208 里,有下划线的是 2,它在百位,数位是 ratus。
注意:题目问数位,就不要回答带 0 的数值。
place value = nilai tempat
Which place is the underlined digit in? Answer with a place name. From left to right a five-digit number has ten thousands, thousands, hundreds, tens and ones; you can also count from the ones on the right.
Example: in 64 208 with 2 underlined, the digit is in the hundreds place, so its place value is ratus.
Watch out: the question asks for a place, so do not answer with a digit value.
Apakah nilai digit bagi digit bergaris dalam 50 863?
数值 = nilai digit
题目问有下划线的数字值多少。先从右往左数,确定它在哪一位;再按数位在数字后面补 0。答案要写成一个数,不是位置的名称。
例子:在 12 604 里,有下划线的 6 在百位,要补两个 0,数值是 600。
注意:补 0 太多或太少,数值都会差十倍以上;位置的名称不是数值。
digit value = nilai digit
What is the underlined digit worth? Count from the right to find its place, then write the digit followed by the right number of zeros. Reply with a number, not a place name.
Example: in 12 604 the underlined 6 is in the hundreds place, so it gets two zeros: its value is 600.
Watch out: one zero too many or too few makes the value ten times wrong, and a place name is not a value.
Pilih cerakinan mengikut nilai digit bagi 63 059.
按数值分解 = cerakin mengikut nilai digit
要找出正确的数值分解式。做法:把原数的每一位写成数值,万位补四个 0,千位补三个 0,以此类推;数字是 0 的数位不用写出来。最后拿每个选项逐部分对照。
例子:41 307 = 40 000 + 1 000 + 300 + 7(十位是 0,所以省略)。
注意:数字是 0 的数位不会出现在分解式里;也要检查每一部分的 0 有没有补对。
digit value breakdown = cerakin mengikut nilai digit
Find the correct breakdown by digit value. Write each digit as its value with the right number of zeros, and leave out any place whose digit is 0. Then check each option part by part.
Example: 41 307 = 40 000 + 1 000 + 300 + 7 (the tens digit is 0, so it is left out).
Watch out: a zero place never appears as a part, and every part must have the right number of zeros.
2 ribu + 7 puluh ribu + 4 puluh + 1 sa = ?
按数位组合 = gabung mengikut nilai tempat
题目把一个数拆成几部分,而且次序打乱了,要把它们合成一个数。做法:画一个五格的数位表,把每一部分放进它的数位;没有提到的数位写 0。最后从左到右读出来。
例子:3 ratus + 5 puluh ribu + 8 sa → 万位 5、千位 0、百位 3、十位 0、个位 8 → 50 308。
注意:不能照题目出现的先后次序写数字,要看每个部分的数位名称。
build from place values = gabung mengikut nilai tempat
The parts of a number are given in mixed order; put them together. Draw a five-place table, put each part in its place and write 0 in any place that is not mentioned. Then read the digits from left to right.
Example: 3 ratus + 5 puluh ribu + 8 sa gives 5, 0, 3, 0, 8 → 50 308.
Watch out: do not copy the digits in the order they appear; use the place name of each part.
90 000 + □ + 7 = 90 607
找缺值 = cari nilai hilang
要找出方框里缺的部分。先把等号右边的数写进数位表,看每一位的数字;再看式子里已经有哪些部分。数字不是 0、而式子里又还没有的那个数位,就是缺的部分,按数位写出它的数值。
例子:40 000 + □ + 2 = 40 052 → 十位是 5,式子里还没有,所以缺 50。
注意:数字是 0 的数位不算缺;要看清缺的数字在哪一位,才知道补几个 0。
find the missing value = cari nilai hilang
Find the part missing from the box. Write the total in a place value table and see which parts the sentence already has. The place with a non-zero digit that is not yet in the sentence is the missing part; write its digit value.
Example: 40 000 + □ + 2 = 40 052; the tens digit 5 is not in the sentence, so the missing part is 50.
Watch out: a zero place is never missing, and check which place the missing digit is in before adding zeros.
Nombor manakah digit 5 bernilai 50 000?
由数值找数 = cari nombor daripada nilai digit
题目给出数字 5 的数值,要找出 5 站在正确位置的那个数。先数数值里有几个 0,就知道 5 要在哪一位:三个 0 是千位,四个 0 是万位。再逐个选项看 5 在哪一位。
例子:数值 4 000 有三个 0,表示 4 在千位,例如 64 918。
注意:同一个数字,放在不同位置,数值就不同;要从右往左数清楚位置。
find a number from a digit value = cari nombor daripada nilai digit
The question gives the value of the digit 5; find the number where 5 is in the right place. Count the zeros in the value: three zeros mean thousands, four zeros mean ten thousands. Then check where the 5 stands in each option.
Example: a value of 4 000 has three zeros, so the 4 is in the thousands place, as in 64 918.
Watch out: the same digit has a different value in a different place, so count the places carefully.
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